-
Either paper 3 marks
The pictogram shows how many books some children collected.
(a)How many books were collected on Tuesday?
(b)Which had the most books?
(c)Calculate the total number of books collected.
Show answer
(a) \(4\)
(b) Thursday
(c) \(31\)One symbol stands for 2 books, so a whole symbol is 2 and a quarter of one is \(2 \div 4\).
The Tuesday row comes to 4.
The longest row is the one with the most books: Thursday, with 10.
Add the four rows:
\(8 + 4 + 9 + 10 = 31\)
-
Either paper 2 marks
The pictogram shows how many apples a fruit shop sold on three days.
(a)On Thursday, 19 apples were sold.
How many whole symbols would be drawn in the Thursday row?
(b)What else would be drawn in that row?
Show answer
(a) \(4\)
(b) three quarters of a symbolOne symbol stands for 4, so work out how many 4s go into 19:
\(19 \div 4 = 4\) remainder \(19 - 4 \times 4\)
So 4 whole symbols are drawn.
After the 4 whole symbols there are \(19 - 4 \times 4\) apples left over.
A whole symbol is 4, so that is three quarters of a symbol.
-
Either paper 4 marks
The pictogram shows how many parcels a courier delivered on four days.
(a)State the number of parcels that half a symbol stands for.
(b)Find the total number of parcels.
(c)Work out how many more parcels are shown for Monday than for Tuesday.
Show answer
(a) \(6\ \text{parcels}\)
(b) \(195\ \text{parcels}\)
(c) \(18\ \text{parcels}\)One whole symbol stands for \(12\) parcels, so half of one stands for half of that.
\(12 \div 2 = 6\) parcels
Read every row against the key first. A quarter of a symbol is a quarter of \(12\), so part-symbols count too.
\(75 + 57 + 36 + 27 = 195\) parcels
\(75 - 57 = 18\) parcels
- (b) M1adding the four rows \(75\), \(57\), \(36\), \(27\)
- (b) A1total \(195\) parcels
-
Either paper 4 marksThe table shows the number of books Owen has in each of four groups.
Shelf Number of books Crime 40 Travel 30 Cookery 65 Sport 35 (a)Which group is the mode?
(b)Owen wants a pictogram to show the information, and has drawn the first two rows.
Complete the pictogram. Remember to complete the key.
You cannot draw on this page. Draw (b) on paper, then show the answer and check your drawing against the model.
Show answer
(a) Cookery
(b) Key: one symbol represents \(10\) books. Cookery: \(6.5\) symbols; Sport: \(3.5\) symbols(b)The mode is the group with the most books: Cookery, with \(65\).
Crime has \(40\) books and its row has \(4\) symbols, so one symbol represents \(40 \div 4 = 10\) books.
Cookery: \(65 \div 10 = 6.5\) symbols
Sport: \(35 \div 10 = 3.5\) symbols
- (b) B1the key: one symbol represents \(10\) books
- (b) B1one of the two rows right for your key
- (b) B1both rows right for your key
-
Either paper 4 marks
The pictogram shows information about the number of plain flapjacks, raisin flapjacks and cherry flapjacks sold by Year 7 at a school fair.
(a)Year 7 sold \(21\) apple flapjacks.
Use this information to complete the pictogram.
(b)At the fair, Year 8 sold a total of \(71\) flapjacks.
Which year sold more flapjacks at the fair, Year 7 or Year 8?
You must show how you get your answer.
You cannot draw on this page. Draw (a) on paper, then show the answer and check your drawing against the model.
Show answer
(a) Apple: \(3.5\) symbols
(b) Year 7: Year 7 sold \(51 + 21 = 72\) flapjacks and Year 8 sold \(71\)(a)One symbol stands for \(6\) flapjacks, so half a symbol stands for \(3\).
\(21 \div 6 = 3.5\)
Draw \(3.5\) symbols in the Apple row.
Each symbol stands for \(6\) flapjacks.
Plain: \(4 \times 6 = 24\), Raisin: \(3 \times 6 = 18\), Cherry: \(1.5 \times 6 = 9\)
\(24 + 18 + 9 = 51\)
Add the Apple row: \(51 + 21 = 72\)
Year 7 sold \(72\) flapjacks and Year 8 sold \(71\), so Year 7 sold more.
- (a) B1Apple row drawn with \(3.5\) symbols
- (b) M1the three rows shown read through the key: \(51\) flapjacks
- (b) M1adding the drawn Apple row: Year 7 total \(72\) flapjacks
- (b) A1Year 7, comparing \(72\) with \(71\)
-
Either paper 5 marks
A library recorded how many visitors came on four days.
The pictogram shows the results, but the key has been left off.
The row for Thursday stands for \(80\) visitors.
(a)Calculate how many visitors one symbol stands for.
(b)Find the number of visitors for Saturday.
(c)Find the total number of visitors over the four rows.
Show answer
(a) \(20\ \text{visitors}\)
(b) \(120\ \text{visitors}\)
(c) \(360\ \text{visitors}\)The Thursday row has \(4\) whole symbols and stands for \(80\) visitors, so share the \(80\) equally between the \(4\) symbols.
\(80 \div 4 = 20\)
One symbol stands for \(20\) visitors.
The Saturday row has \(6\) symbols, and each one is worth \(20\).
\(6 \times 20 = 120\) visitors
There are \(4 + 5 + 6 + 3 = 18\) symbols altogether, and each one is worth \(20\).
\(18 \times 20 = 360\) visitors
- (a) M1dividing \(80\) by the number of symbols \(4\)
- (a) A1one symbol stands for \(20\)
- (c) M1total number of symbols \(18\)
- (c) A1total \(360\) visitors
-
Either paper 4 marks
Four scouts sold raffle tickets at a fair.
The pictogram shows the results for the first three only.
Altogether there were \(47\) tickets.
(a)Work out the number of tickets shown on the pictogram.
(b)Work out the number of tickets for Mina.
(c)Work out how many symbols the row for Mina would have.
Show answer
(a) \(39\ \text{tickets}\)
(b) \(8\ \text{tickets}\)
(c) \(2\)Read each row against the key, remembering that part of a symbol is that fraction of \(4\).
\(8 + 11 + 20 = 39\) tickets
The four together came to \(47\), and the three drawn rows account for \(39\).
\(47 - 39 = 8\) tickets
Each symbol stands for \(4\) tickets.
\(8 \div 4 = 2\) symbols
- (a) M1reading each row against the key: \(8\), \(11\) and \(20\) tickets
- (a) A1total shown \(39\) tickets
-
Either paper 3 marks
Misha recorded the main type of weather each day. The total is \(275\) days.
The pictogram shows the results for Rain, Snow and Cloud. The rows for Sun and Fog are missing.
The number for Sun was \(30\) more than the number for Fog.
Work out the two missing numbers and complete the pictogram.
You cannot draw on this page. Draw this on paper, then show the answer and check your drawing against the model.
Show answer
Sun: \(7.5\) symbols; Fog: \(4.5\) symbolsRead the three rows through the key, where half a symbol is \(5\).
\(55 + 65 + 35 = 155\) days
That leaves \(275 - 155 = 120\) for Sun and Fog together.
Sun is \(30\) more than Fog, so take the \(30\) off and halve what is left.
Fog: \((120 - 30) \div 2 = 45\), and Sun: \(45 + 30 = 75\)
Each symbol stands for \(10\), so Sun has \(75 \div 10 = 7.5\) symbols and Fog has \(45 \div 10 = 4.5\) symbols.
- B1one of the two rows with the right number of symbols
- B2both rows right: Sun \(7.5\) symbols and Fog \(4.5\) symbols
-
Either paper 2 marksBen asked 36 pupils to choose their favourite fruit. The table shows the results.
Ben drew this pictogram to show the results. Ben has made two mistakes. What are they? Mistake 1 Mistake 2Fruit Number of pupils Apple 7 Banana 8 Grapes 10 Orange 11 Show answer
Mistake 1: the Apple row has 3 symbols and should have 3.5 (half a symbol too few). Mistake 2: one row has no label (or: the pictogram has no title).Each symbol stands for \(2\) pupils, so a row of \(n\) pupils needs \(n \div 2\) symbols.
Apple: \(7 \div 2 = 3.5\) symbols
Banana: \(8 \div 2 = 4\) symbols
Grapes: \(10 \div 2 = 5\) symbols
Orange: \(11 \div 2 = 5.5\) symbols
Only the Apple row differs: it is drawn with \(3\) symbols, not \(3.5\).
The second mistake: one row has no label. (The pictogram also has no title, which is accepted instead.)
- B1the Apple row is wrong: \(7\) pupils needs \(7 \div 2 = 3.5\) symbols, not \(3\)
- B1one row has no label, or the pictogram has no title
-
Either paper 4 marks
Groups A and B of learner drivers took driving tests. The pictogram shows the number of people in group A who passed after one, two and three tests.
Group A
(a) The table gives the number of people in each row for group B.
Complete the pictogram for group B. Group BTests taken Group B One test 3 fewer than the number in group A Two tests half the number in group A Three tests double the number in group A (b)Calculate the total number of people in group B.
You cannot draw on this page. Draw (a) on paper, then show the answer and check your drawing against the model.
Show answer
(a) One test: \(0.5\) symbol; Two tests: \(2.5\) symbols; Three tests: \(5\) symbols
(b) \(48\)(a)Read each row of group A through the key, then use the table. One symbol stands for \(6\) people, so half a symbol is \(3\).
One test: group A has \(1\) symbol, which is \(6\). To take away: \(6 − 3 = 3\), which is \(3 ÷ 6 = 0.5\) symbol.
Two tests: group A has \(5\) symbols, which is \(30\). To halve: \(30 ÷ 2 = 15\), which is \(15 ÷ 6 = 2.5\) symbols.
Three tests: group A has \(2.5\) symbols, which is \(15\). To double: \(15 × 2 = 30\), which is \(30 ÷ 6 = 5\) symbols.
\(3 + 15 + 30 = 48\)
- (a) B1one row with the right number of symbols
- (a) B1two rows with the right number of symbols
- (a) B1all three rows right: \(0.5\), \(2.5\) and \(5\) symbols