Vectors Proof Questions worksheet
8 GCSE practice questions with answers, free to print. Every sheet is generated, so you can make a fresh one whenever you need it.
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5 marks
\(OAB\) is a triangle.
\(\overrightarrow{OA} = 2\mathbf{a}\) and \(\overrightarrow{OB} = 6\mathbf{b}\).
\(X\) is the point on \(OA\) such that \(OX : XA = 1 : 1\), and \(Y\) is the point on \(OB\) such that \(OY : YB = 1 : 1\).
(a)Write \(\overrightarrow{XY}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(b)Show that \(XY\) is parallel to \(AB\), and write down the ratio \(XY : AB\).
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7 marks
\(OABC\) is a parallelogram. \(X\) is the midpoint of the diagonal \(AC\).
\(\overrightarrow{OA} = 6\mathbf{a}\) and \(\overrightarrow{OC} = 4\mathbf{b}\).
(a)Express \(\overrightarrow{AC}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(b)Express \(\overrightarrow{OX}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(c)Prove that \(O\), \(X\) and \(B\) lie on the same straight line.
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1 mark
The points \(A\), \(B\) and \(C\) have position vectors, relative to an origin \(O\),
\(\overrightarrow{OA} = 4\mathbf{a} + 2\mathbf{b}\)
\(\overrightarrow{OB} = 6\mathbf{a} + 3\mathbf{b}\)
\(\overrightarrow{OC} = 12\mathbf{a} + 6\mathbf{b}\)
where \(\mathbf{a}\) and \(\mathbf{b}\) are not parallel.
Prove that \(A\), \(B\) and \(C\) lie on the same straight line.
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6 marks
\(OABC\) is a trapezium. \(M\) is the midpoint of \(BC\).
\(\overrightarrow{OA} = 4\mathbf{a}\), \(\overrightarrow{AB} = 4\mathbf{b}\) and \(\overrightarrow{OC} = 12\mathbf{b}\).
(a)Find \(\overrightarrow{BC}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(b)Find \(\overrightarrow{OM}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
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7 marks
\(OABC\) is a parallelogram. \(P\) is the midpoint of \(AB\) and \(Q\) is the midpoint of \(BC\).
\(\overrightarrow{OA} = 6\mathbf{a}\) and \(\overrightarrow{OC} = 4\mathbf{b}\).
(a)Express \(\overrightarrow{AC}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(b)Express \(\overrightarrow{PQ}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(c)Show that \(PQ\) is parallel to \(AC\), and write down the ratio \(PQ : AC\).
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5 marks
\(OAB\) is a triangle.
\(\overrightarrow{OA} = 6\mathbf{a}\) and \(\overrightarrow{OB} = 9\mathbf{b}\).
\(X\) is the point on \(OA\) such that \(OX : XA = 1 : 2\), and \(Y\) is the point on \(OB\) such that \(OY : YB = 1 : 2\).
(a)Find \(\overrightarrow{XY}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(b)Show that \(XY\) is parallel to \(AB\), and write down the ratio \(XY : AB\).
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7 marks
\(OABC\) is a parallelogram. \(X\) is the midpoint of the diagonal \(AC\).
\(\overrightarrow{OA} = 10\mathbf{a}\) and \(\overrightarrow{OC} = 8\mathbf{b}\).
(a)Find \(\overrightarrow{AC}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(b)Find \(\overrightarrow{OX}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
(c)Prove that \(O\), \(X\) and \(B\) lie on the same straight line.
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1 mark
Relative to an origin \(O\), the points \(A\), \(B\) and \(C\) have position vectors
\(\overrightarrow{OA} = 2\mathbf{a} + 3\mathbf{b}\)
\(\overrightarrow{OB} = 11\mathbf{a} + 6\mathbf{b}\)
\(\overrightarrow{OC} = 14\mathbf{a} + 7\mathbf{b}\)
where \(\mathbf{a}\) and \(\mathbf{b}\) are not parallel.
Prove that \(A\), \(B\) and \(C\) lie on the same straight line.
Answers
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(a) \(3\mathbf{b} - \mathbf{a}\)
(b) \(\overrightarrow{AB} = 6\mathbf{b} - 2\mathbf{a} = 2\left(3\mathbf{b} - \mathbf{a}\right) = 2\,\overrightarrow{XY}\), so \(XY\) is parallel to \(AB\), and \(XY : AB = 1 : 2\) -
(a) \(4\mathbf{b} - 6\mathbf{a}\)
(b) \(3\mathbf{a} + 2\mathbf{b}\)
(c) \(\overrightarrow{OB} = 6\mathbf{a} + 4\mathbf{b} = 2\left(3\mathbf{a} + 2\mathbf{b}\right) = 2\,\overrightarrow{OX}\), so \(OB\) is parallel to \(OX\) and they share the point \(O\); therefore \(O\), \(X\) and \(B\) are on one straight line - \(\overrightarrow{AB} = 2\mathbf{a} + \mathbf{b}\) and \(\overrightarrow{BC} = 6\mathbf{a} + 3\mathbf{b} = 3\,\overrightarrow{AB}\), so \(AB\) and \(BC\) are parallel and share the point \(B\); therefore \(A\), \(B\) and \(C\) are on one straight line
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(a) \(8\mathbf{b} - 4\mathbf{a}\)
(b) \(2\mathbf{a} + 8\mathbf{b}\) -
(a) \(4\mathbf{b} - 6\mathbf{a}\)
(b) \(2\mathbf{b} - 3\mathbf{a}\)
(c) \(\overrightarrow{AC} = 4\mathbf{b} - 6\mathbf{a} = 2\left(2\mathbf{b} - 3\mathbf{a}\right) = 2\,\overrightarrow{PQ}\), so \(PQ\) is parallel to \(AC\), and \(PQ : AC = 1 : 2\) -
(a) \(3\mathbf{b} - 2\mathbf{a}\)
(b) \(\overrightarrow{AB} = 9\mathbf{b} - 6\mathbf{a} = 3\left(3\mathbf{b} - 2\mathbf{a}\right) = 3\,\overrightarrow{XY}\), so \(XY\) is parallel to \(AB\), and \(XY : AB = 1 : 3\) -
(a) \(8\mathbf{b} - 10\mathbf{a}\)
(b) \(5\mathbf{a} + 4\mathbf{b}\)
(c) \(\overrightarrow{OB} = 10\mathbf{a} + 8\mathbf{b} = 2\left(5\mathbf{a} + 4\mathbf{b}\right) = 2\,\overrightarrow{OX}\), so \(OB\) is parallel to \(OX\) and they share the point \(O\); therefore \(O\), \(X\) and \(B\) are on one straight line - \(\overrightarrow{AB} = 9\mathbf{a} + 3\mathbf{b}\) and \(\overrightarrow{BC} = 3\mathbf{a} + \mathbf{b} = \frac{1}{3}\,\overrightarrow{AB}\), so \(AB\) and \(BC\) are parallel and share the point \(B\); therefore \(A\), \(B\) and \(C\) are on one straight line