The Sine Rule
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Either paper 1 mark
Here is a triangle.
Circle the correct equation.
\(\frac{ x }{ \sin 51^\circ } = \frac{ 16 }{ \sin 62^\circ }\) \(\frac{ x }{ 62^\circ } = \frac{ 16 }{ \sin 51^\circ }\)
\(\frac{ x }{ \sin 62^\circ } = \frac{ 16 }{ \sin 51^\circ }\) \(\frac{ \sin 51^\circ }{ x } = \frac{ 16 }{ \sin 62^\circ }\)
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Calculator 3 marks
\(ABC\) is a triangle.
Calculate the length of \(AC\).
Give your answer to 3 significant figures.
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Calculator 3 marks
\(ABC\) is a triangle.
Calculate the size of the angle marked \(x\).
Give your answer to 1 decimal place.
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Calculator 4 marks
\(ABC\) is a triangle.
(a)Find the size of angle \(ACB\).
(b)Find the length of \(BC\).
Give your answer correct to 1 decimal place.
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Calculator 4 marks
\(P\) and \(Q\) are two survey posts, \(860\) m apart. A ferry is at \(R\).
The angle \(RPQ\) is \(59^\circ\) and the angle \(PQR\) is \(70^\circ\).
Find the distance \(QR\).
Give your answer correct to the nearest metre.
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Calculator 4 marks
A triangular lawn \(PQR\) has \(QR = 25\) m and \(PQ = 22\) m.
Angle \(QPR = 78^\circ\).
(a)Find the size of angle \(PRQ\).
Give your answer correct to 1 decimal place.
(b)Find the size of angle \(PQR\).
Give your answer correct to 1 decimal place.
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Calculator 6 marks
A boat sails \(47\) km north from \(A\) to \(B\).
From \(B\) the boat sails to \(C\) and then back to \(A\).
\(BC = 70\) km and the bearing of \(C\) from \(B\) is \(040^\circ\).
(a)Show that the distance the boat sails from \(C\) to \(A\) is \(110\) km to the nearest km.
You must show your working.
(b)Work out the bearing of \(A\) from \(C\).
Use your unrounded value of \(CA\) from part (a), not the value to the nearest km.
Give your answer to the nearest degree.
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Calculator 5 marks
\(ABC\) is a triangle.
(a)Find the size of the angle at \(C\).
(b)Find the perimeter of the triangle.
Give your answer to 1 decimal place.
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Calculator 6 marks
\(ABC\) is a triangle.
(a)Work out the length of \(AC\).
Give your answer correct to 1 decimal place.
(b)Work out the size of angle \(BAC\).
Give your answer correct to the nearest degree.
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Calculator 4 marks
In triangle \(ABC\), \(BC = 7\) cm, \(AB = 12\) cm and angle \(BAC = 30^\circ\).
Angle \(ACB\) is obtuse.
Work out the size of angle \(ACB\).
Give your answer to 1 decimal place.
- \(\frac{ x }{ \sin 62^\circ } = \frac{ 16 }{ \sin 51^\circ }\)
- \(7.55\ \text{cm}\)
- \(53.8^\circ\)
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(a) \(97^\circ\)
(b) \(5.1\ \text{cm}\) - \(949\ \text{m}\)
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(a) \(59.4^\circ\)
(b) \(42.6^\circ\) -
(a) Angle \(ABC = 140^\circ\), so \(CA^2 \approx 12149.57\) and \(CA \approx 110.23\) km \(\approx 110\) km
(b) \(204^\circ\) -
(a) \(54^\circ\)
(b) \(25.6\ \text{cm}\) -
(a) \(9.9\ \text{cm}\)
(b) \(45^\circ\) - \(121.0^\circ\)
Takes a couple of seconds the first time a sheet is made.