Discia GCSE Maths › Algebra › Rearranging Harder Formulae

Rearranging Harder Formulae worksheet

10 GCSE practice questions with answers, free to print. Every sheet is generated, so you can make a fresh one whenever you need it.

10 questions 54 marks Sheet 1
Generate a different sheet
  1. 6 marks
    (a)

    Make \(x\) the subject of \(5x + y = x + 12\)

    (b)

    Make \(x\) the subject of \(y\left(x + 3\right) = 5x - 6\)

  2. 4 marks

    Make \(x\) the subject of \(y = \frac{ 3x + 7 }{x - 5 }\)

  3. 6 marks
    (a)

    Make \(x\) the subject of \(y = \sqrt{ 7x + 15 }\)

    (b)

    Make \(x\) the subject of \(y = 6\sqrt{x} - 7\)

  4. 6 marks
    (a)

    Rearrange \(y = \frac{ 11 }{ x } + 12\) to make \(x\) the subject.

    (b)

    Rearrange \(y = \frac{ 9 }{x - 2 }\) to make \(x\) the subject.

  5. 5 marks

    A car moving in a straight line starts at a speed of \(u\) metres per second and finishes at a speed of \(v\) metres per second. Its acceleration is \(a\) metres per second squared and it travels a distance of \(s\) metres.

    Those four are connected by the formula

    \(v^2 = u^2 + 2as\)

    (a)

    Rearrange the formula to make \(u\) the subject.

    (b)

    Work out \(u\) when \(v = 11\), \(a = 8\) and \(s = 7\).

  6. 6 marks
    (a)

    Make \(x\) the subject of \(7x + y = x - 13\)

    (b)

    Make \(x\) the subject of \(y\left(x + 1\right) = 6x + 3\)

  7. 4 marks

    Make \(x\) the subject of \(y = \frac{ x - 9 }{x - 5 }\)

  8. 6 marks
    (a)

    Rearrange \(y = \sqrt{ 9x + 13 }\) to make \(x\) the subject.

    (b)

    Rearrange \(y = 5\sqrt{x} + 2\) to make \(x\) the subject.

  9. 6 marks
    (a)

    Make \(x\) the subject of \(y = \frac{ 15 }{ x } - 2\)

    (b)

    Make \(x\) the subject of \(y = \frac{ 15 }{x + 2 }\)

  10. 5 marks

    A car moving in a straight line starts at a speed of \(u\) metres per second and finishes at a speed of \(v\) metres per second. Its acceleration is \(a\) metres per second squared and it travels a distance of \(s\) metres.

    Those four are connected by the formula

    \(v^2 = u^2 + 2as\)

    (a)

    Rearrange the formula to make \(u\) the subject.

    (b)

    Work out \(u\) when \(v = 15\), \(a = 8\) and \(s = 11\).

Answers

  1. (a) \(x = \frac{ 12 - y}{ 4 }\)
    (b) \(x = \frac{ -6 - 3y }{y - 5 }\)
  2. \(x = \frac{ 7 + 5y }{y - 3 }\)
  3. (a) \(x = \frac{y^2 - 15 }{ 7 }\)
    (b) \(x = \frac{\left(y + 7\right)^2}{ 36 }\)
  4. (a) \(x = \frac{ 11 }{y - 12 }\)
    (b) \(x = \frac{ 9 }{ y } + 2\)
  5. (a) \(u = \sqrt{v^2 - 2as}\)
    (b) \(3\ \text{m/s}\)
  6. (a) \(x = \frac{ -13 - y}{ 6 }\)
    (b) \(x = \frac{ 3 -y }{y - 6 }\)
  7. \(x = \frac{ -9 + 5y }{y - 1 }\)
  8. (a) \(x = \frac{y^2 - 13 }{ 9 }\)
    (b) \(x = \frac{\left(y - 2\right)^2}{ 25 }\)
  9. (a) \(x = \frac{ 15 }{y + 2 }\)
    (b) \(x = \frac{ 15 }{ y } - 2\)
  10. (a) \(u = \sqrt{v^2 - 2as}\)
    (b) \(7\ \text{m/s}\)

← All GCSE maths worksheets

{# Self-hosted. The public pages make no third-party request at all — see docs/PUBLIC_LAUNCH_HANDOFF.md before pointing this at a CDN again. #}