Quadratic Inequalities
-
Either paper 2 marks
\(x^2 - 11x + 28 \lt 0\)
Is \(x = 6\) a solution of this inequality?
You must show your working.
-
Either paper Higher1 mark
Here is a sketch of \(y = f(x)\) where \(f(x)\) is a quadratic function.
The graph crosses the \(x\)-axis where \(x = -2.5\) and \(x = -1\)
Circle the solution of \(f(x) > 0\)
\(x < -2.5 \text{ or } x > -1\)
\(-2.5 < x < -1\)
\(x < -2.5 \text{ or } x < -1\)
\(x > -2.5 \text{ or } x > -1\)
-
Either paper Higher1 mark
Write down the solution of \(x^2 \gt 25\)
-
Either paper Higher4 marks
The graph of \(y = x^2 - 6x + 5\) is drawn on the grid.
(a)Use the graph to solve \(x^2 - 6x + 5 < 0\)
(b)Use the graph to solve \(x^2 - 6x + 5 > 0\)
-
Either paper Higher3 marks
Solve \(4x^2 \gt 64\)
-
Either paper 1 mark
Yusuf has solved the inequality \(x^2 \gt 49\) and shown the solution on the number line.
Give a value of \(x\) that shows Yusuf's solution is wrong, and say why.
-
Either paper Higher3 marks
Solve \(x^2 -x - 6 < 0\)
-
Either paper Higher3 marks
Solve the inequality \(x^2 + 8x + 15 \geq 0\)
-
Either paper Higher3 marks
List all the integers that satisfy \(x^2 + 8x + 7 \leq 0\)
-
Either paper Higher4 marks
Solve \(x^2 > -5x + 14\)
- Yes. When \(x = 6\) the expression is equal to \(-2\), which is less than zero.
- \(-2.5 < x < -1\)
- \(x \lt -5\) or \(x \gt 5\)
-
(a) \(1 < x < 5\)
(b) \(x < 1\) or \(x > 5\) - \(x \lt -4\) or \(x \gt 4\)
- For example \(x = 8\): it is not shaded on the line, but \(8^2 = 64\) is more than 49, so it should be shaded. Any value that is shaded when it does not work, or not shaded when it works, is correct. The values that work are outside \(-7\) and \(7\).
- \(-2 < x < 3\)
- \(x \leq -5\) or \(x \geq -3\)
- \(-7,\ -6,\ -5,\ -4,\ -3,\ -2,\ -1\)
- \(x < -7\) or \(x > 2\)
Takes a couple of seconds the first time a sheet is made.