Equation of a circle
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Either paper 2 marks(a)
A circle has centre \(O\), the origin, and radius \(18\).
Write down the equation of the circle.
(b)A different circle has equation \(x^2 + y^2 = 196\)
Write down the radius of this circle.
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Either paper 3 marks
The circle \(C\) has equation \(x^2 + y^2 = 9\)
(a)Write down the coordinates of the two points where \(C\) crosses the \(y\)-axis.
(b)State the coordinates of the point where \(C\) crosses the negative \(x\)-axis.
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Calculator 3 marks
A circle has centre the origin and equation \(x^2 + y^2 = 52\)
(a)Calculate the radius of the circle.
Give your answer in the form \(a\sqrt{b}\), where \(a\) and \(b\) are integers and \(b\) is as small as possible.
(b)Calculate the radius correct to 1 decimal place.
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Either paper 3 marks
The circle \(C\) has equation \(x^2 + y^2 = 400\)
Does the point \((-12, 17)\) lie inside \(C\), on \(C\), or outside \(C\)?
You must show your working.
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Either paper 3 marks
A circle has centre \(O\), the origin, and passes through the point \((-12, 5)\).
(a)Find the equation of the circle.
(b)Write down the radius of the circle.
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Either paper 7 marks
\(A\), \(B\) and \(C\) are points on the circle \(x^2 + y^2 = 64\). The circle is not drawn; the points are shown on the axes.
\(A\) is on the \(y\)-axis.
\(B\) is on the \(x\)-axis.
\(M\) is the midpoint of \(AB\).
\(COM\) is a straight line.
(a)Show that the coordinates of \(A\) are \((0, 8)\).
(b)Work out the coordinates of \(B\).
(c)Show that the equation of the straight line passing through \(C\), \(O\) and \(M\) is \(y = -x\).
(d)Work out the coordinates of \(C\).
Give your answer in surd form.
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Either paper 5 marks(a)
On the grid, draw the graph of \(x^2 + y^2 = 64\)
On the same grid, draw the graph of \(6y = -x\)
(b)Use your graphs to find estimates for the solutions of the simultaneous equations
\(x^2 + y^2 = 64\)
\(6y = -x\)
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Either paper 3 marks
The point \((15, k)\) lies on the circle \(x^2 + y^2 = 625\)
Given that \(k\) is positive, work out the value of \(k\).
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Calculator 4 marks
The diagram shows a circle, centre \(O\), drawn on coordinate axes with \(O\) at the origin.
\(BA\) is the tangent to the circle at the point \(A\).
Angle \(OBA = 52^\circ\)
Point \(B\) has coordinates \((27, 0)\).
Point \(P\) has coordinates \((2p, p)\) and lies on the circle, where \(p > 0\).
Work out the value of \(p\).
Give your answer correct to 1 decimal place.
You must show all your working.
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Either paper 4 marks
A circle has equation \(x^2 + y^2 = 100\)
The point \(P(-6, 8)\) lies on the circle.
Nadia says that the tangent to the circle at \(P\) crosses the \(y\)-axis at the point \((0, 16)\).
Is Nadia correct?
You must show how you get your answer.
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(a) \(x^2 + y^2 = 324\)
(b) \(14\) -
(a) \((0, 3)\) and \((0, -3)\)
(b) \((-3, 0)\) -
(a) \(2\sqrt{ 13 }\)
(b) \(7.2\) - Outside the circle
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(a) \(x^2 + y^2 = 169\)
(b) \(13\) -
(a) \(y^2 = 64\), so \(y = 8\) (above \(O\)): \(A = (0, 8)\)
(b) \((-8, 0)\)
(c) \(M = (-4, 4)\), gradient \(-1\), through \(O\): \(y = -x\)
(d) \((4\sqrt{2}, -4\sqrt{2})\) -
(a) A circle with centre \(O\) (the origin) and radius \(8\), and the straight line through \(O\) and \((6, -1)\)
(b) About \((7.9, -1.3)\) and \((-7.9, 1.3)\) (each coordinate within 0.3)(a) - \(20\)
- \(9.5\)
- No: the tangent crosses the \(y\)-axis at \((0, 12.5)\)
Takes a couple of seconds the first time a sheet is made.