Changing the Subject of a Formula
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Either paper 3 marks(a)
Make \(x\) the subject of \(y = x - 13\)
(b)Make \(t\) the subject of \(w = 5t\)
(c)Make \(k\) the subject of \(p = \frac{k}{ 4 }\)
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Either paper 1 mark\(ab^{3} = c\) Circle the correct expression for \(a\).
\(cb^{3}\) \(3bc\) \(\frac{ c }{ b^{3} }\) \(\frac{ c }{ 3b }\) -
Either paper 2 marks
Make \(x\) the subject of the formula \(y = 3x + 2\)
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Either paper 2 marks
Rearrange the formula \(y = \frac{x}{ 3 } + 5\) to make \(x\) the subject.
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Either paper 4 marks
A hire shop uses the formula
\(C = 4d + 15\)
to work out the cost, \(C\) pounds, of hiring a carpet cleaner for \(d\) days.
(a)Make \(d\) the subject of the formula.
(b)Priya pays £43 to hire the carpet cleaner.
Find the number of days she hires it for.
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Either paper 2 marks
Make \(x\) the subject of the formula \(y = \frac{ x - 17 }{ 6 }\)
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Either paper 2 marks
Rearrange the formula \(y = 5(x + 8)\) to make \(x\) the subject.
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Either paper 2 marks
Make \(x\) the subject of the formula \(y = 40 - 2x\)
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Either paper 3 marks
Make \(x\) the subject of the formula \(y = \frac{ 3x }{ 8 } + 20\)
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Either paper 2 marks
Rearrange the formula \(y = 82 - \frac{x}{ 4 }\) to make \(x\) the subject.
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(a) \(x = y + 13\)
(b) \(t = \frac{w}{ 5 }\)
(c) \(k = 4p\) - \(\frac{ c }{ b^{3} }\)
- \(x = \frac{y - 2 }{ 3 }\)
- \(x = 3(y - 5)\)
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(a) \(d = \frac{C - 15 }{ 4 }\)
(b) \(7\ \text{days}\) - \(x = 6y + 17\)
- \(x = \frac{ y }{ 5 } - 8\)
- \(x = \frac{ 40 - y }{ 2 }\)
- \(x = \frac{ 8(y - 20) }{ 3 }\)
- \(x = 4(82 - y)\)
Takes a couple of seconds the first time a sheet is made.